Oracle中的OOP概念
添加时间: 2008-4-29 1:20:20 作者: Oracle指导 阅读次数:99 来源: http://www.d9soft.com
p_person person) return employee)
/
desc employee
在类型主体实现这两个方法：
create or replace
type body employee as
member function total_compensation return number is
begin
return nvl(self.sal,0) + nvl(self.commission, 0);
end;
static function new(p_empno number,
p_person person) return employee is
begin
return employee(p_person,p_empno,sysdate,10000,null);
end;
end;
/
比较抽象数据类型的数据：
declare
l_employee1 employee;
l_employee2 employee;
begin
l_employee1 :=employee.new(12345,null);
l_employee2 :=employee.new(67890,null);
if l_employee1= l_employee2 then
dbms_output.line_put(“They are equal”);
end if;
end;
/
使用map指定具体比较哪些属性：
create or replace
type employee as object(
name person,
empno number,
hiredate date,
sal number,
commission number,
map member function convert return number)
/
create or replace
type body employee as
map member function convert return number is
begin
return self.empno;
end;
end;
/
再比较：
declare
l_employee1 employee;
l_employee2 employee;
begin
l_employee1 :=employee.new(12345,null);
l_employee2 :=employee.new(67890,null);
if l_employee1= l_employee2 then
dbms_output.line_put(“They are equal”);
end if;
if l_employee1> l_employee2 then
dbms_output.line_put(“employee1 is greater”);
end if;
if l_employee1< l_employee2 then
dbms_output.line_put(“employee2 is greater”);
end if;
end;
/
Order 方法：
create or replace
type employee as object(
name person,
empno number,
hiredate date,
sal number,
commission number,
order member function match(p_employee employee) return integer)
/
create or replace
type body employee as
order member function match(p_employee employee) return integer is
begin
if self.empno> p_employee.empno then
return 1;
elseif self.empno< p_employee.empno then
return -1;
else
return 0;
end if;
end;
end;
/
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